(y-7)(2y^2+7y-15)=0

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Solution for (y-7)(2y^2+7y-15)=0 equation:


Simplifying
(y + -7)(2y2 + 7y + -15) = 0

Reorder the terms:
(-7 + y)(2y2 + 7y + -15) = 0

Reorder the terms:
(-7 + y)(-15 + 7y + 2y2) = 0

Multiply (-7 + y) * (-15 + 7y + 2y2)
(-7(-15 + 7y + 2y2) + y(-15 + 7y + 2y2)) = 0
((-15 * -7 + 7y * -7 + 2y2 * -7) + y(-15 + 7y + 2y2)) = 0
((105 + -49y + -14y2) + y(-15 + 7y + 2y2)) = 0
(105 + -49y + -14y2 + (-15 * y + 7y * y + 2y2 * y)) = 0
(105 + -49y + -14y2 + (-15y + 7y2 + 2y3)) = 0

Reorder the terms:
(105 + -49y + -15y + -14y2 + 7y2 + 2y3) = 0

Combine like terms: -49y + -15y = -64y
(105 + -64y + -14y2 + 7y2 + 2y3) = 0

Combine like terms: -14y2 + 7y2 = -7y2
(105 + -64y + -7y2 + 2y3) = 0

Solving
105 + -64y + -7y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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